forked from jasder/antlr
Remove the RuleContext.hashCode, equals, conflictsWith, and suffix methods since they produce unexpected behavior for ParserRuleContext and are no longer used for adaptivePredict
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27cb0e4012
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@ -73,33 +73,12 @@ public class RuleContext implements RuleNode {
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*/
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public int invokingState = -1;
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/** Computing the hashCode is very expensive and closureBusy()
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* uses it to track when it's seen a state|ctx before to avoid
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* infinite loops. As we add new contexts, record the hash code
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* as this.invokingState + parent.cachedHashCode. Avoids walking
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* up the tree for every hashCode(). Note that this caching works
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* because a context is a monotonically growing tree of context nodes
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* and nothing on the stack is ever modified...ctx just grows
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* or shrinks.
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*/
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protected int cachedHashCode;
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public RuleContext() {}
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public RuleContext(RuleContext parent, int invokingState) {
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this.parent = parent;
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//if ( parent!=null ) System.out.println("invoke "+stateNumber+" from "+parent);
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this.invokingState = invokingState;
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this.cachedHashCode = invokingState;
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if ( parent!=null ) {
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this.cachedHashCode += parent.cachedHashCode;
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}
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}
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@Override
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public int hashCode() {
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return cachedHashCode; // works with tests; don't recompute.
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}
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public int depth() {
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@ -112,100 +91,6 @@ public class RuleContext implements RuleNode {
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return n;
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}
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/** Two contexts are equals() if both have
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* same call stack; walk upwards to the root.
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* Note that you may be comparing contexts in different alt trees.
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*
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* The hashCode is cheap as it's computed once upon each context
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* push on the stack. Using it to make equals() more efficient.
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*/
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@Override
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public boolean equals(Object o) {
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if (this == o) {
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return true;
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} else if (!(o instanceof RuleContext)) {
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return false;
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}
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RuleContext other = (RuleContext)o;
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if ( this.hashCode() != other.hashCode() ) {
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return false; // can't be same if hash is different
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}
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// System.out.println("comparing "+this+" with "+other);
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RuleContext sp = this;
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while ( sp!=null && other!=null ) {
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if ( sp == other ) return true;
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if ( sp.invokingState != other.invokingState) return false;
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sp = sp.parent;
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other = other.parent;
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}
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if ( !(sp==null && other==null) ) {
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return false; // both pointers must be at their roots after walk
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}
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return true;
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}
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/** Two contexts conflict() if they are equals() or one is a stack suffix
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* of the other. For example, contexts [21 12 $] and [21 9 $] do not
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* conflict, but [21 $] and [21 12 $] do conflict. Note that I should
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* probably not show the $ in this case. There is a dummy node for each
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* stack that just means empty; $ is a marker that's all.
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*
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* This is used in relation to checking conflicts associated with a
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* single NFA state's configurations within a single DFA state.
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* If there are configurations s and t within a DFA state such that
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* s.state=t.state && s.alt != t.alt && s.ctx conflicts t.ctx then
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* the DFA state predicts more than a single alt--it's nondeterministic.
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* Two contexts conflict if they are the same or if one is a suffix
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* of the other.
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*
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* When comparing contexts, if one context has a stack and the other
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* does not then they should be considered the same context. The only
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* way for an NFA state p to have an empty context and a nonempty context
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* is the case when closure falls off end of rule without a call stack
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* and re-enters the rule with a context. This resolves the issue I
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* discussed with Sriram Srinivasan Feb 28, 2005 about not terminating
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* fast enough upon nondeterminism.
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*/
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public boolean conflictsWith(RuleContext other) {
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return this.suffix(other) || this.equals(other);
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}
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/** [$] suffix any context
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* [21 $] suffix [21 12 $]
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* [21 12 $] suffix [21 $]
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* [21 18 $] suffix [21 18 12 9 $]
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* [21 18 12 9 $] suffix [21 18 $]
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* [21 12 $] not suffix [21 9 $]
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*
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* Example "[21 $] suffix [21 12 $]" means: rule r invoked current rule
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* from state 21. Rule s invoked rule r from state 12 which then invoked
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* current rule also via state 21. While the context prior to state 21
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* is different, the fact that both contexts emanate from state 21 implies
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* that they are now going to track perfectly together. Once they
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* converged on state 21, there is no way they can separate. In other
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* words, the prior stack state is not consulted when computing where to
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* go in the closure operation. x$ and xy$ are considered the same stack.
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* If x is popped off then $ and y$ remain; they are now an empty and
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* nonempty context comparison. So, if one stack is a suffix of
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* another, then it will still degenerate to the simple empty stack
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* comparison case.
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*/
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protected boolean suffix(RuleContext other) {
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RuleContext sp = this;
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// if one of the contexts is empty, it never enters loop and returns true
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while ( sp.parent!=null && other.parent!=null ) {
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if ( sp.invokingState != other.invokingState ) {
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return false;
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}
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sp = sp.parent;
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other = other.parent;
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}
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//System.out.println("suffix");
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return true;
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}
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/** A context is empty if there is no invoking state; meaning nobody call
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* current context.
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*/
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