63 lines
2.1 KiB
Python
63 lines
2.1 KiB
Python
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from django.http import HttpResponseForbidden
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from django.template import Context, Template
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from django.conf import settings
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# We include the template inline since we need to be able to reliably display
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# this error message, especially for the sake of developers, and there isn't any
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# other way of making it available independent of what is in the settings file.
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CSRF_FAILRE_TEMPLATE = """
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
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<html lang="en">
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<head>
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<meta http-equiv="content-type" content="text/html; charset=utf-8">
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<title>403 Forbidden</title>
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</head>
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<body>
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<h1>403 Forbidden</h1>
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<p>CSRF verification failed. Request aborted.</p>
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{% if DEBUG %}
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<h2>Help</h2>
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{% if reason %}
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<p>Reason given for failure:</p>
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<pre>
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{{ reason }}
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</pre>
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{% endif %}
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<p>In general, this can occur when there is a genuine Cross Site Request Forgery, or when
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<a
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href='http://docs.djangoproject.com/en/dev/ref/contrib/csrf/#ref-contrib-csrf'>Django's
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CSRF mechanism</a> has not been used correctly. For POST forms, you need to
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ensure:</p>
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<ul>
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<li>The view function uses <a
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href='http://docs.djangoproject.com/en/dev/ref/templates/api/#subclassing-context-requestcontext'><tt>RequestContext</tt></a>
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for the template, instead of <tt>Context</tt>.</li>
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<li>In the template, there is a <tt>{% templatetag openblock %} csrf_token
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{% templatetag closeblock %}</tt> template tag inside each POST form that
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targets an internal URL.</li>
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</ul>
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<p>You're seeing the help section of this page because you have <code>DEBUG =
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True</code> in your Django settings file. Change that to <code>False</code>,
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and only the initial error message will be displayed. </p>
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<p>You can customize this page using the CSRF_FAILURE_VIEW setting.</p>
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{% endif %}
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</body>
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</html>
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"""
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def csrf_failure(request, reason=""):
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"""
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Default view used when request fails CSRF protection
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"""
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t = Template(CSRF_FAILRE_TEMPLATE)
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c = Context({'DEBUG': settings.DEBUG,
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'reason': reason})
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return HttpResponseForbidden(t.render(c), mimetype='text/html')
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