Fixed #10089 -- Corrected handling of aggregates when the query set contains no items (and the cursor returns None). Thanks to Kyle Fox for the report, and david for the initial patch.

git-svn-id: http://code.djangoproject.com/svn/django/trunk@9786 bcc190cf-cafb-0310-a4f2-bffc1f526a37
This commit is contained in:
Russell Keith-Magee 2009-01-23 11:03:48 +00:00
parent ed3d2735a2
commit 0e15932be3
5 changed files with 35 additions and 3 deletions

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@ -217,6 +217,8 @@ class BaseQuery(object):
to return Decimal and long types when they are not needed.
"""
if value is None:
if aggregate.is_ordinal:
return 0
# Return None as-is
return value
elif aggregate.is_ordinal:
@ -295,10 +297,14 @@ class BaseQuery(object):
query.related_select_cols = []
query.related_select_fields = []
result = query.execute_sql(SINGLE)
if result is None:
result = [None for q in query.aggregate_select.items()]
return dict([
(alias, self.resolve_aggregate(val, aggregate))
for (alias, aggregate), val
in zip(query.aggregate_select.items(), query.execute_sql(SINGLE))
in zip(query.aggregate_select.items(), result)
])
def get_count(self):

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@ -31,6 +31,14 @@
"num_awards": 9
}
},
{
"pk": 5,
"model": "aggregation.publisher",
"fields": {
"name": "Jonno's House of Books",
"num_awards": 0
}
},
{
"pk": 1,
"model": "aggregation.book",

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@ -194,7 +194,7 @@ u'The Definitive Guide to Django: Web Development Done Right'
# Annotate each publisher with the sum of the price of all books sold
>>> publishers = Publisher.objects.all().annotate(Sum('book__price'))
>>> sorted([(p.name, p.book__price__sum) for p in publishers])
[(u'Apress', Decimal("59.69")), (u'Morgan Kaufmann', Decimal("75.00")), (u'Prentice Hall', Decimal("112.49")), (u'Sams', Decimal("23.09"))]
[(u'Apress', Decimal("59.69")), (u"Jonno's House of Books", None), (u'Morgan Kaufmann', Decimal("75.00")), (u'Prentice Hall', Decimal("112.49")), (u'Sams', Decimal("23.09"))]
# Calls to values() are not commutative over annotate().
@ -356,7 +356,7 @@ True
[]
# Aggregates also work on dates, times and datetimes
>>> Publisher.objects.annotate(earliest_book=Min('book__pubdate')).order_by('earliest_book').values()
>>> Publisher.objects.annotate(earliest_book=Min('book__pubdate')).exclude(earliest_book=None).order_by('earliest_book').values()
[{'earliest_book': datetime.date(1991, 10, 15), 'num_awards': 9, 'id': 4, 'name': u'Morgan Kaufmann'}, {'earliest_book': datetime.date(1995, 1, 15), 'num_awards': 7, 'id': 3, 'name': u'Prentice Hall'}, {'earliest_book': datetime.date(2007, 12, 6), 'num_awards': 3, 'id': 1, 'name': u'Apress'}, {'earliest_book': datetime.date(2008, 3, 3), 'num_awards': 1, 'id': 2, 'name': u'Sams'}]
>>> Store.objects.aggregate(Max('friday_night_closing'), Min("original_opening"))

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@ -31,6 +31,14 @@
"num_awards": 9
}
},
{
"pk": 5,
"model": "aggregation_regress.publisher",
"fields": {
"name": "Jonno's House of Books",
"num_awards": 0
}
},
{
"pk": 1,
"model": "aggregation_regress.book",

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@ -164,6 +164,16 @@ FieldError: Cannot resolve keyword 'foo' into field. Choices are: authors, id, i
>>> len(Book.objects.annotate(num_authors=Count('authors')).exclude(num_authors__lt=2).filter(num_authors__lt=3))
2
# Regression for #10089: Check handling of empty result sets with aggregates
>>> Book.objects.filter(id__in=[]).count()
0
>>> Book.objects.filter(id__in=[]).aggregate(num_authors=Count('authors'), avg_authors=Avg('authors'), max_authors=Max('authors'), max_price=Max('price'), max_rating=Max('rating'))
{'max_authors': None, 'max_rating': None, 'num_authors': 0, 'avg_authors': None, 'max_price': None}
>>> Publisher.objects.filter(pk=5).annotate(num_authors=Count('book__authors'), avg_authors=Avg('book__authors'), max_authors=Max('book__authors'), max_price=Max('book__price'), max_rating=Max('book__rating')).values()
[{'max_authors': None, 'name': u"Jonno's House of Books", 'num_awards': 0, 'max_price': None, 'num_authors': 0, 'max_rating': None, 'id': 5, 'avg_authors': None}]
"""
}