Fixed #3184 -- Changed the `unordered_list` template filter to use a more simple format, while maintaining backwards compatibility with the old format. `unordered_list` now works with a simple list of items. Thanks for the patch, SmileyChris.
git-svn-id: http://code.djangoproject.com/svn/django/trunk@6019 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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@ -355,8 +355,8 @@ def unordered_list(value):
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Recursively takes a self-nested list and returns an HTML unordered list --
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WITHOUT opening and closing <ul> tags.
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The list is assumed to be in the proper format. For example, if ``var`` contains
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``['States', [['Kansas', [['Lawrence', []], ['Topeka', []]]], ['Illinois', []]]]``,
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The list is assumed to be in the proper format. For example, if ``var``
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contains: ``['States', ['Kansas', ['Lawrence', 'Topeka'], 'Illinois']]``,
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then ``{{ var|unordered_list }}`` would return::
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<li>States
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@ -371,14 +371,61 @@ def unordered_list(value):
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</ul>
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</li>
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"""
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def _helper(value, tabs):
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def convert_old_style_list(list_):
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"""
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Converts old style lists to the new easier to understand format.
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The old list format looked like:
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['Item 1', [['Item 1.1', []], ['Item 1.2', []]]
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And it is converted to:
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['Item 1', ['Item 1.1', 'Item 1.2]]
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"""
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if not isinstance(list_, (tuple, list)) or len(list_) != 2:
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return list_, False
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first_item, second_item = list_
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if second_item == []:
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return [first_item], True
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old_style_list = True
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new_second_item = []
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for sublist in second_item:
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item, old_style_list = convert_old_style_list(sublist)
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if not old_style_list:
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break
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new_second_item.extend(item)
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if old_style_list:
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second_item = new_second_item
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return [first_item, second_item], old_style_list
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def _helper(list_, tabs=1):
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indent = u'\t' * tabs
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if value[1]:
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return u'%s<li>%s\n%s<ul>\n%s\n%s</ul>\n%s</li>' % (indent, force_unicode(value[0]), indent,
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u'\n'.join([_helper(v, tabs+1) for v in value[1]]), indent, indent)
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else:
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return u'%s<li>%s</li>' % (indent, force_unicode(value[0]))
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return _helper(value, 1)
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output = []
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list_length = len(list_)
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i = 0
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while i < list_length:
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title = list_[i]
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sublist = ''
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sublist_item = None
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if isinstance(title, (list, tuple)):
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sublist_item = title
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title = ''
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elif i < list_length - 1:
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next_item = list_[i+1]
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if next_item and isinstance(next_item, (list, tuple)):
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# The next item is a sub-list.
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sublist_item = next_item
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# We've processed the next item now too.
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i += 1
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if sublist_item:
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sublist = _helper(sublist_item, tabs+1)
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sublist = '\n%s<ul>\n%s\n%s</ul>\n%s' % (indent, sublist,
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indent, indent)
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output.append('%s<li>%s%s</li>' % (indent, force_unicode(title),
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sublist))
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i += 1
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return '\n'.join(output)
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value, converted = convert_old_style_list(value)
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return _helper(value)
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###################
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# INTEGERS #
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@ -1301,9 +1301,14 @@ unordered_list
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Recursively takes a self-nested list and returns an HTML unordered list --
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WITHOUT opening and closing <ul> tags.
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**Changed in Django development version**
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The format accepted by ``unordered_list`` has changed to an easier to
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understand format.
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The list is assumed to be in the proper format. For example, if ``var`` contains
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``['States', [['Kansas', [['Lawrence', []], ['Topeka', []]]], ['Illinois', []]]]``,
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then ``{{ var|unordered_list }}`` would return::
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``['States', ['Kansas', ['Lawrence', 'Topeka'], 'Illinois']]``, then
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``{{ var|unordered_list }}`` would return::
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<li>States
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<ul>
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@ -1317,6 +1322,9 @@ then ``{{ var|unordered_list }}`` would return::
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</ul>
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</li>
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Note: the previous more restrictive and verbose format is still supported:
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``['States', [['Kansas', [['Lawrence', []], ['Topeka', []]]], ['Illinois', []]]]``,
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upper
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~~~~~
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@ -266,6 +266,22 @@ u'bc'
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>>> slice_(u'abcdefg', u'0::2')
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u'aceg'
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>>> unordered_list([u'item 1', u'item 2'])
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u'\t<li>item 1</li>\n\t<li>item 2</li>'
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>>> unordered_list([u'item 1', [u'item 1.1']])
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u'\t<li>item 1\n\t<ul>\n\t\t<li>item 1.1</li>\n\t</ul>\n\t</li>'
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>>> unordered_list([u'item 1', [u'item 1.1', u'item1.2'], u'item 2'])
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u'\t<li>item 1\n\t<ul>\n\t\t<li>item 1.1</li>\n\t\t<li>item1.2</li>\n\t</ul>\n\t</li>\n\t<li>item 2</li>'
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>>> unordered_list([u'item 1', [u'item 1.1', [u'item 1.1.1', [u'item 1.1.1.1']]]])
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u'\t<li>item 1\n\t<ul>\n\t\t<li>item 1.1\n\t\t<ul>\n\t\t\t<li>item 1.1.1\n\t\t\t<ul>\n\t\t\t\t<li>item 1.1.1.1</li>\n\t\t\t</ul>\n\t\t\t</li>\n\t\t</ul>\n\t\t</li>\n\t</ul>\n\t</li>'
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>>> unordered_list(['States', ['Kansas', ['Lawrence', 'Topeka'], 'Illinois']])
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u'\t<li>States\n\t<ul>\n\t\t<li>Kansas\n\t\t<ul>\n\t\t\t<li>Lawrence</li>\n\t\t\t<li>Topeka</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>Illinois</li>\n\t</ul>\n\t</li>'
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# Old format for unordered lists should still work
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>>> unordered_list([u'item 1', []])
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u'\t<li>item 1</li>'
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@ -275,6 +291,9 @@ u'\t<li>item 1\n\t<ul>\n\t\t<li>item 1.1</li>\n\t</ul>\n\t</li>'
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>>> unordered_list([u'item 1', [[u'item 1.1', []], [u'item 1.2', []]]])
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u'\t<li>item 1\n\t<ul>\n\t\t<li>item 1.1</li>\n\t\t<li>item 1.2</li>\n\t</ul>\n\t</li>'
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>>> unordered_list(['States', [['Kansas', [['Lawrence', []], ['Topeka', []]]], ['Illinois', []]]])
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u'\t<li>States\n\t<ul>\n\t\t<li>Kansas\n\t\t<ul>\n\t\t\t<li>Lawrence</li>\n\t\t\t<li>Topeka</li>\n\t\t</ul>\n\t\t</li>\n\t\t<li>Illinois</li>\n\t</ul>\n\t</li>'
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>>> add(u'1', u'2')
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3
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