From 1b0e58811841858a6108ea7188625d3bd0d41ace Mon Sep 17 00:00:00 2001
From: Malcolm Tredinnick <malcolm.tredinnick@gmail.com>
Date: Thu, 13 Sep 2007 23:30:26 +0000
Subject: [PATCH] Fixed #4793 -- Tweaked custom filter documentation a little
 to possibly reduce some confusion. Thanks, SmileyChris.

git-svn-id: http://code.djangoproject.com/svn/django/trunk@6143 bcc190cf-cafb-0310-a4f2-bffc1f526a37
---
 docs/templates_python.txt | 32 +++++++++++++++++++-------------
 1 file changed, 19 insertions(+), 13 deletions(-)

diff --git a/docs/templates_python.txt b/docs/templates_python.txt
index 261eaedf74..150aa70fdf 100644
--- a/docs/templates_python.txt
+++ b/docs/templates_python.txt
@@ -642,7 +642,23 @@ your function. Example::
         "Converts a string into all lowercase"
         return value.lower()
 
-When you've written your filter definition, you need to register it with
+Template filters which expect strings
+~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+
+If you're writing a template filter which only expects a string as the first
+argument, you should use the included decorator ``stringfilter``. This will
+convert an object to it's string value before being passed to your function::
+
+    from django.template.defaultfilters import stringfilter
+
+    @stringfilter
+    def lower(value):
+        return value.lower()
+
+Registering a custom filters
+~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+
+Once you've written your filter definition, you need to register it with
 your ``Library`` instance, to make it available to Django's template language::
 
     register.filter('cut', cut)
@@ -658,28 +674,18 @@ If you're using Python 2.4 or above, you can use ``register.filter()`` as a
 decorator instead::
 
     @register.filter(name='cut')
+    @stringfilter
     def cut(value, arg):
         return value.replace(arg, '')
 
     @register.filter
+    @stringfilter
     def lower(value):
         return value.lower()
 
 If you leave off the ``name`` argument, as in the second example above, Django
 will use the function's name as the filter name.
 
-Template filters which expect strings
-~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-If you are writing a template filter which only expects a string as the first
-argument, you should use the included decorator ``stringfilter`` which will convert
-an object to it's string value before being passed to your function::
-
-    from django.template.defaultfilters import stringfilter
-
-    @stringfilter
-    def lower(value):
-        return value.lower()
-
 Writing custom template tags
 ----------------------------