Fixed #10028 -- Fixed a problem when ordering by related models.
Some results were inadvertently being excluded if we were ordering across a nullable relation which itself ordering by a non-nullable relation. git-svn-id: http://code.djangoproject.com/svn/django/trunk@9916 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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@ -834,8 +834,9 @@ class BaseQuery(object):
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# the model.
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self.ref_alias(alias)
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# Must use left outer joins for nullable fields.
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self.promote_alias_chain(joins)
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# Must use left outer joins for nullable fields and their relations.
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self.promote_alias_chain(joins,
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self.alias_map[joins[0]][JOIN_TYPE] == self.LOUTER)
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# If we get to this point and the field is a relation to another model,
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# append the default ordering for that model.
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@ -238,6 +238,32 @@ class PointerA(models.Model):
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class PointerB(models.Model):
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connection = models.ForeignKey(SharedConnection)
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# Multi-layer ordering
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class SingleObject(models.Model):
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name = models.CharField(max_length=10)
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class Meta:
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ordering = ['name']
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def __unicode__(self):
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return self.name
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class RelatedObject(models.Model):
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single = models.ForeignKey(SingleObject)
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class Meta:
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ordering = ['single']
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class Plaything(models.Model):
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name = models.CharField(max_length=10)
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others = models.ForeignKey(RelatedObject, null=True)
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class Meta:
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ordering = ['others']
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def __unicode__(self):
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return self.name
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__test__ = {'API_TESTS':"""
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>>> t1 = Tag.objects.create(name='t1')
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@ -1044,6 +1070,11 @@ Bug #9985 -- qs.values_list(...).values(...) combinations should work.
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>>> Annotation.objects.filter(notes__in=Note.objects.filter(note="n1").values_list('note').values('id'))
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[<Annotation: a1>]
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Bug #10028 -- ordering by model related to nullable relations(!) should use
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outer joins, so that all results are included.
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>>> _ = Plaything.objects.create(name="p1")
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>>> Plaything.objects.all()
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[<Plaything: p1>]
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"""}
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# In Python 2.3 and the Python 2.6 beta releases, exceptions raised in __len__
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