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[1.7.x] Clean up syncdb parts of migrate output if no synced apps

This commit is contained in:
Andrew Godwin 2014-06-22 13:03:25 -07:00
parent f577b2db3c
commit 72d1c4a6dd
1 changed files with 3 additions and 3 deletions
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6
django/core/management/commands/migrate.py
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@ -108,8 +108,8 @@ class Command(BaseCommand):
# Print some useful info
if self.verbosity >= 1:
self.stdout.write(self.style.MIGRATE_HEADING("Operations to perform:"))
if run_syncdb:
self.stdout.write(self.style.MIGRATE_LABEL(" Synchronize unmigrated apps: ") + (", ".join(executor.loader.unmigrated_apps) or "(none)"))
if run_syncdb and executor.loader.unmigrated_apps:
self.stdout.write(self.style.MIGRATE_LABEL(" Synchronize unmigrated apps: ") + (", ".join(executor.loader.unmigrated_apps)))
if target_app_labels_only:
self.stdout.write(self.style.MIGRATE_LABEL(" Apply all migrations: ") + (", ".join(set(a for a, n in targets)) or "(none)"))
else:
@ -122,7 +122,7 @@ class Command(BaseCommand):
# If you ever manage to get rid of this, I owe you many, many drinks.
# Note that pre_migrate is called from inside here, as it needs
# the list of models about to be installed.
if run_syncdb:
if run_syncdb and executor.loader.unmigrated_apps:
if self.verbosity >= 1:
self.stdout.write(self.style.MIGRATE_HEADING("Synchronizing apps without migrations:"))
created_models = self.sync_apps(connection, executor.loader.unmigrated_apps)