Fixed #3664 -- Documented that get_absolute_url() and item_link() (in

syndication) links are expected to be strings that can be used in URLs without
further quoting or encoding.


git-svn-id: http://code.djangoproject.com/svn/django/trunk@5250 bcc190cf-cafb-0310-a4f2-bffc1f526a37
This commit is contained in:
Malcolm Tredinnick 2007-05-15 18:03:00 +00:00
parent a10e73ac30
commit 7969c1bb65
2 changed files with 13 additions and 1 deletions

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@ -1759,6 +1759,15 @@ But this template code is good::
<a href="{{ object.get_absolute_url }}">{{ object.name }}</a> <a href="{{ object.get_absolute_url }}">{{ object.name }}</a>
.. note::
The string you return from ``get_absolute_url()`` must be use only ASCII
characters (required by the URI spec, `RFC 2396`_) that has been
URL-encoded, if necessary. Code and templates using ``get_absolute_url()``
should be able to use the result directly without needing to do any
further processing.
.. _RFC 2396: http://www.ietf.org/rfc/rfc2396.txt
The ``permalink`` decorator The ``permalink`` decorator
~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~

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@ -146,7 +146,10 @@ put into those elements.
exist, it tries calling a method ``item_link()`` in the ``Feed`` class, exist, it tries calling a method ``item_link()`` in the ``Feed`` class,
passing it a single parameter, ``item``, which is the object itself. passing it a single parameter, ``item``, which is the object itself.
Both ``get_absolute_url()`` and ``item_link()`` should return the item's Both ``get_absolute_url()`` and ``item_link()`` should return the item's
URL as a normal Python string. URL as a normal Python string. As with ``get_absolute_url()``, the
result of ``item_link()`` will be included directly in the URL, so you
are responsible for doing all necessary URL quoting and conversion to
ASCII inside the method itself.
* For the LatestEntries example above, we could have very simple feed templates: * For the LatestEntries example above, we could have very simple feed templates: