Fix NoneType error when fetching a stale ContentType with get_for_id

When a stale ContentType is fetched, the _add_to_cache() function
didn't detect that `model_class()` returns `None` (which it does by
design). However, the `app_label` + `model` fields can be used instead
to as local cache key. Third party apps can detect stale models by
checking whether `model_class()` returns `None`.

Ticket: https://code.djangoproject.com/ticket/20442
This commit is contained in:
Diederik van der Boor 2013-05-18 17:27:12 +02:00
parent 96cabba808
commit 86e761fee8
2 changed files with 11 additions and 2 deletions

View File

@ -118,11 +118,13 @@ class ContentTypeManager(models.Manager):
def _add_to_cache(self, using, ct):
"""Insert a ContentType into the cache."""
model = ct.model_class()
key = (model._meta.app_label, model._meta.model_name)
# Note it's possible for ContentType objects to be stale; model_class() will return None.
# Hence, there is no reliance on model._meta.app_label here, just using the model fields instead.
key = (ct.app_label, ct.model)
self.__class__._cache.setdefault(using, {})[key] = ct
self.__class__._cache.setdefault(using, {})[ct.id] = ct
@python_2_unicode_compatible
class ContentType(models.Model):
name = models.CharField(max_length=100)

View File

@ -274,3 +274,10 @@ class ContentTypesTests(TestCase):
model = 'OldModel',
)
self.assertEqual(six.text_type(ct), 'Old model')
self.assertIsNone(ct.model_class())
# Make sure stale ContentTypes can be fetched like any other object.
# Before Django 1.6 this caused a NoneType error in the caching mechanism.
# Instead, just return the ContentType object and let the app detect stale states.
ct_fetched = ContentType.objects.get_for_id(ct.pk)
self.assertIsNone(ct_fetched.model_class())