Small clarifications to docs/forms.txt change from [3466]

git-svn-id: http://code.djangoproject.com/svn/django/trunk@3474 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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Adrian Holovaty 2006-07-28 02:30:36 +00:00
parent 8753a072f7
commit e5b51925ac
1 changed files with 14 additions and 7 deletions

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@ -408,20 +408,22 @@ Here's a simple function that might drive the above form::
``FileField``s and ``ImageField``s ``FileField``s and ``ImageField``s
================================== ==================================
Dealing with for ``FileField`` and ``ImageField`` is a little more Dealing with ``FileField``s and ``ImageField``s is a little more
complicated. complicated.
First, you'll need to make sure that your ``<form>`` element correctly defines First, you'll need to make sure that your ``<form>`` element correctly defines
the ``enctype`` in order to upload files:: the ``enctype`` as ``"multipart/form-data"``, in order to upload files::
<form enctype="multipart/form-data" method="POST" action="."> <form enctype="multipart/form-data" method="post" action="/foo/">
Next, you'll need to treat the field in the template slightly differently. Next, you'll need to treat the field in the template slightly differently. A
Given a field in the model:: ``FileField`` or ``ImageField`` is represented by *two* HTML form elements.
For example, given this field in a model::
photo = model.ImageField('/path/to/upload/location') photo = model.ImageField('/path/to/upload/location')
You need to actually display two formfields in the template: You'd need to display two formfields in the template::
<p><label for="id_photo">Photo:</label> {{ form.photo }}{{ form.photo_file }}</p> <p><label for="id_photo">Photo:</label> {{ form.photo }}{{ form.photo_file }}</p>
@ -430,7 +432,12 @@ while the second (``{{ form.photo_file }}``) actually contains the file upload
form field. Thus, at the validation layer you need to check the ``photo_file`` form field. Thus, at the validation layer you need to check the ``photo_file``
key. key.
Finally, in the view, make sure to call ``new_data.update(request.FILES)``:: Finally, in your view, make sure to access ``request.FILES``, rather than
``request.POST``, for the uploaded files. This is necessary because
``request.POST`` does not contain file-upload data.
For example, following the ``new_data`` convention, you might do something like
this::
new_data = request.POST.copy() new_data = request.POST.copy()
new_data.update(request.FILES) new_data.update(request.FILES)