Fixed #9067: Added a note that you can register a model with the admin without providing a ModelAdmin object. Thanks to Rob Hudson for the suggestion.
git-svn-id: http://code.djangoproject.com/svn/django/trunk@9024 bcc190cf-cafb-0310-a4f2-bffc1f526a37
This commit is contained in:
parent
7ab3285f64
commit
e600d00b44
|
@ -50,6 +50,20 @@ Let's take a look at a very simple example the ``ModelAdmin``::
|
||||||
pass
|
pass
|
||||||
admin.site.register(Author, AuthorAdmin)
|
admin.site.register(Author, AuthorAdmin)
|
||||||
|
|
||||||
|
.. admonition:: Do you need a ``ModelAdmin`` object at all?
|
||||||
|
|
||||||
|
In the preceding example, the ``ModelAdmin`` class doesn't define any
|
||||||
|
custom values (yet). As a result, the default admin interface will be
|
||||||
|
provided. If you are happy with the default admin interface, you don't
|
||||||
|
need to define a ``ModelAdmin`` object at all -- you can register the
|
||||||
|
model class without providing a ``ModelAdmin`` description. The
|
||||||
|
preceding example could be simplified to::
|
||||||
|
|
||||||
|
from django.contrib import admin
|
||||||
|
from myproject.myapp.models import Author
|
||||||
|
|
||||||
|
admin.site.register(Author)
|
||||||
|
|
||||||
``ModelAdmin`` Options
|
``ModelAdmin`` Options
|
||||||
----------------------
|
----------------------
|
||||||
|
|
||||||
|
|
Loading…
Reference in New Issue