[1.7.x] Use the new implementation of `six.with_metaclass`.
No more `NewBase` horrors.
Thanks to bendavis78 for his work on merging this into six.
Backport of a2340ac6d6
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@ -62,19 +62,9 @@ class ModelBase(type):
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def __new__(cls, name, bases, attrs):
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super_new = super(ModelBase, cls).__new__
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# six.with_metaclass() inserts an extra class called 'NewBase' in the
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# inheritance tree: Model -> NewBase -> object. But the initialization
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# should be executed only once for a given model class.
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# attrs will never be empty for classes declared in the standard way
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# (ie. with the `class` keyword). This is quite robust.
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if name == 'NewBase' and attrs == {}:
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return super_new(cls, name, bases, attrs)
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# Also ensure initialization is only performed for subclasses of Model
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# (excluding Model class itself).
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parents = [b for b in bases if isinstance(b, ModelBase) and
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not (b.__name__ == 'NewBase' and b.__mro__ == (b, object))]
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parents = [b for b in bases if isinstance(b, ModelBase)]
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if not parents:
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return super_new(cls, name, bases, attrs)
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@ -628,7 +628,21 @@ _add_doc(reraise, """Reraise an exception.""")
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def with_metaclass(meta, *bases):
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"""Create a base class with a metaclass."""
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return meta("NewBase", bases, {})
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# This requires a bit of explanation: the basic idea is to make a
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# dummy metaclass for one level of class instantiation that replaces
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# itself with the actual metaclass. Because of internal type checks
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# we also need to make sure that we downgrade the custom metaclass
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# for one level to something closer to type (that's why __call__ and
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# __init__ comes back from type etc.).
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class metaclass(meta):
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__call__ = type.__call__
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__init__ = type.__init__
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def __new__(cls, name, this_bases, d):
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if this_bases is None:
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return type.__new__(cls, name, (), d)
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return meta(name, bases, d)
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return metaclass('temporary_class', None, {})
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def add_metaclass(metaclass):
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"""Class decorator for creating a class with a metaclass."""
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