Fixed #15208 - Document ModelAdmin.formfield_for_choice_field; thanks julien.
git-svn-id: http://code.djangoproject.com/svn/django/trunk@15399 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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@ -927,6 +927,25 @@ templates used by the :class:`ModelAdmin` views:
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kwargs["queryset"] = Car.objects.filter(owner=request.user)
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return super(MyModelAdmin, self).formfield_for_manytomany(db_field, request, **kwargs)
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.. method:: ModelAdmin.formfield_for_choice_field(self, db_field, request, **kwargs)
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Like the ``formfield_for_foreignkey`` and ``formfield_for_manytomany``
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methods, the ``formfield_for_choice_field`` method can be overridden to
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change the default formfield for a field that has declared choices. For
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example, if the choices available to a superuser should be different than
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those available to regular staff, you could proceed as follows::
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class MyModelAdmin(admin.ModelAdmin):
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def formfield_for_choice_field(self, db_field, request, **kwargs):
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if db_field.name == "status":
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kwargs['choices'] = (
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('accepted', 'Accepted'),
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('denied', 'Denied'),
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)
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if request.user.is_superuser:
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kwargs['choices'] += (('ready', 'Ready for deployment'),)
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return super(MyModelAdmin, self).formfield_for_choice_field(db_field, request, **kwargs)
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.. method:: ModelAdmin.has_add_permission(self, request)
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Should return ``True`` if adding an object is permitted, ``False``
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