# These classes override date and datetime to ensure that strftime('%Y') # returns four digits (with leading zeros) on years < 1000. # https://bugs.python.org/issue13305 # # Based on code submitted to comp.lang.python by Andrew Dalke # # >>> datetime_safe.date(10, 8, 2).strftime("%Y/%m/%d was a %A") # '0010/08/02 was a Monday' import time import warnings from datetime import date as real_date, datetime as real_datetime from django.utils.deprecation import RemovedInDjango50Warning from django.utils.regex_helper import _lazy_re_compile warnings.warn( 'The django.utils.datetime_safe module is deprecated.', category=RemovedInDjango50Warning, stacklevel=2, ) class date(real_date): def strftime(self, fmt): return strftime(self, fmt) class datetime(real_datetime): def strftime(self, fmt): return strftime(self, fmt) @classmethod def combine(cls, date, time): return cls(date.year, date.month, date.day, time.hour, time.minute, time.second, time.microsecond, time.tzinfo) def date(self): return date(self.year, self.month, self.day) def new_date(d): "Generate a safe date from a datetime.date object." return date(d.year, d.month, d.day) def new_datetime(d): """ Generate a safe datetime from a datetime.date or datetime.datetime object. """ kw = [d.year, d.month, d.day] if isinstance(d, real_datetime): kw.extend([d.hour, d.minute, d.second, d.microsecond, d.tzinfo]) return datetime(*kw) # This library does not support strftime's "%s" or "%y" format strings. # Allowed if there's an even number of "%"s because they are escaped. _illegal_formatting = _lazy_re_compile(r"((^|[^%])(%%)*%[sy])") def _findall(text, substr): # Also finds overlaps sites = [] i = 0 while True: i = text.find(substr, i) if i == -1: break sites.append(i) i += 1 return sites def strftime(dt, fmt): if dt.year >= 1000: return super(type(dt), dt).strftime(fmt) illegal_formatting = _illegal_formatting.search(fmt) if illegal_formatting: raise TypeError('strftime of dates before 1000 does not handle ' + illegal_formatting[0]) year = dt.year # For every non-leap year century, advance by # 6 years to get into the 28-year repeat cycle delta = 2000 - year off = 6 * (delta // 100 + delta // 400) year = year + off # Move to around the year 2000 year = year + ((2000 - year) // 28) * 28 timetuple = dt.timetuple() s1 = time.strftime(fmt, (year,) + timetuple[1:]) sites1 = _findall(s1, str(year)) s2 = time.strftime(fmt, (year + 28,) + timetuple[1:]) sites2 = _findall(s2, str(year + 28)) sites = [] for site in sites1: if site in sites2: sites.append(site) s = s1 syear = "%04d" % dt.year for site in sites: s = s[:site] + syear + s[site + 4:] return s