django1/django/contrib/localflavor/se/utils.py

85 lines
2.3 KiB
Python

import re
import datetime
def id_number_checksum(gd):
"""
Calculates a Swedish ID number checksum, using the
"Luhn"-algoritm
"""
n = s = 0
for c in (gd['year'] + gd['month'] + gd['day'] + gd['serial']):
tmp = ((n % 2) and 1 or 2) * int(c)
if tmp > 9:
tmp = sum([int(i) for i in str(tmp)])
s += tmp
n += 1
if (s % 10) == 0:
return 0
return (((s / 10) + 1) * 10) - s
def validate_id_birthday(gd, fix_coordination_number_day=True):
"""
Validates the birth_day and returns the datetime.date object for
the birth_day.
If the date is an invalid birth day, a ValueError will be raised.
"""
today = datetime.date.today()
day = int(gd['day'])
if fix_coordination_number_day and day > 60:
day -= 60
if gd['century'] is None:
# The century was not specified, and need to be calculated from todays date
current_year = today.year
year = int(today.strftime('%Y')) - int(today.strftime('%y')) + int(gd['year'])
if ('%s%s%02d' % (gd['year'], gd['month'], day)) > today.strftime('%y%m%d'):
year -= 100
# If the person is older than 100 years
if gd['sign'] == '+':
year -= 100
else:
year = int(gd['century'] + gd['year'])
# Make sure the year is valid
# There are no swedish personal identity numbers where year < 1800
if year < 1800:
raise ValueError
# ValueError will be raise for invalid dates
birth_day = datetime.date(year, int(gd['month']), day)
# birth_day must not be in the future
if birth_day > today:
raise ValueError
return birth_day
def format_personal_id_number(birth_day, gd):
# birth_day.strftime cannot be used, since it does not support dates < 1900
return unicode(str(birth_day.year) + gd['month'] + gd['day'] + gd['serial'] + gd['checksum'])
def format_organisation_number(gd):
if gd['century'] is None:
century = ''
else:
century = gd['century']
return unicode(century + gd['year'] + gd['month'] + gd['day'] + gd['serial'] + gd['checksum'])
def valid_organisation(gd):
return gd['century'] in (None, 16) and \
int(gd['month']) >= 20 and \
gd['sign'] in (None, '-') and \
gd['year'][0] in ('2', '5', '7', '8', '9') # group identifier