34 lines
1.4 KiB
Python
34 lines
1.4 KiB
Python
from django.core.management.base import CopyFilesCommand, CommandError
|
|
import os
|
|
|
|
class Command(CopyFilesCommand):
|
|
help = "Creates a Django app directory structure for the given app name in the current directory."
|
|
args = "[appname]"
|
|
|
|
requires_model_validation = False
|
|
# Can't import settings during this command, because they haven't
|
|
# necessarily been created.
|
|
can_import_settings = False
|
|
|
|
def handle(self, app_name, directory=None, **options):
|
|
if directory is None:
|
|
directory = os.getcwd()
|
|
# Determine the project_name a bit naively -- by looking at the name of
|
|
# the parent directory.
|
|
project_dir = os.path.normpath(os.path.join(directory, '..'))
|
|
parent_dir = os.path.basename(project_dir)
|
|
project_name = os.path.basename(directory)
|
|
if app_name == project_name:
|
|
raise CommandError("You cannot create an app with the same name (%r) as your project." % app_name)
|
|
self.copy_helper('app', app_name, directory, parent_dir)
|
|
|
|
class ProjectCommand(Command):
|
|
help = "Creates a Django app directory structure for the given app name in this project's directory."
|
|
|
|
def __init__(self, project_directory):
|
|
super(ProjectCommand, self).__init__()
|
|
self.project_directory = project_directory
|
|
|
|
def handle(self, app_name, **options):
|
|
super(ProjectCommand, self).handle(app_name, self.project_directory, **options)
|