django1/tests/modeltests/unmanaged_models/models.py

153 lines
4.1 KiB
Python

"""
Models can have a ``managed`` attribute, which specifies whether the SQL code
is generated for the table on various manage.py operations.
"""
from django.db import models
# All of these models are creatd in the database by Django.
class A01(models.Model):
f_a = models.CharField(max_length=10, db_index=True)
f_b = models.IntegerField()
class Meta:
db_table = 'A01'
def __unicode__(self):
return self.f_a
class B01(models.Model):
fk_a = models.ForeignKey(A01)
f_a = models.CharField(max_length=10, db_index=True)
f_b = models.IntegerField()
class Meta:
db_table = 'B01'
# 'managed' is True by default. This tests we can set it explicitly.
managed = True
def __unicode__(self):
return self.f_a
class C01(models.Model):
mm_a = models.ManyToManyField(A01, db_table='D01')
f_a = models.CharField(max_length=10, db_index=True)
f_b = models.IntegerField()
class Meta:
db_table = 'C01'
def __unicode__(self):
return self.f_a
# All of these models use the same tables as the previous set (they are shadows
# of possibly a subset of the columns). There should be no creation errors,
# since we have told Django they aren't managed by Django.
class A02(models.Model):
f_a = models.CharField(max_length=10, db_index=True)
class Meta:
db_table = 'A01'
managed = False
def __unicode__(self):
return self.f_a
class B02(models.Model):
class Meta:
db_table = 'B01'
managed = False
fk_a = models.ForeignKey(A02)
f_a = models.CharField(max_length=10, db_index=True)
f_b = models.IntegerField()
def __unicode__(self):
return self.f_a
# To re-use the many-to-many intermediate table, we need to manually set up
# things up.
class C02(models.Model):
mm_a = models.ManyToManyField(A02, through="Intermediate")
f_a = models.CharField(max_length=10, db_index=True)
f_b = models.IntegerField()
class Meta:
db_table = 'C01'
managed = False
def __unicode__(self):
return self.f_a
class Intermediate(models.Model):
a02 = models.ForeignKey(A02, db_column="a01_id")
c02 = models.ForeignKey(C02, db_column="c01_id")
class Meta:
db_table = 'D01'
managed = False
#
# These next models test the creation (or not) of many to many join tables
# between managed and unmanaged models. A join table between two unmanaged
# models shouldn't be automatically created (see #10647).
#
# Firstly, we need some models that will create the tables, purely so that the
# tables are created. This is a test setup, not a requirement for unmanaged
# models.
class Proxy1(models.Model):
class Meta:
db_table = "unmanaged_models_proxy1"
class Proxy2(models.Model):
class Meta:
db_table = "unmanaged_models_proxy2"
class Unmanaged1(models.Model):
class Meta:
managed = False
db_table = "unmanaged_models_proxy1"
# Unmanged with an m2m to unmanaged: the intermediary table won't be created.
class Unmanaged2(models.Model):
mm = models.ManyToManyField(Unmanaged1)
class Meta:
managed = False
db_table = "unmanaged_models_proxy2"
# Here's an unmanaged model with an m2m to a managed one; the intermediary
# table *will* be created (unless given a custom `through` as for C02 above).
class Managed1(models.Model):
mm = models.ManyToManyField(Unmanaged1)
__test__ = {'API_TESTS':"""
The main test here is that the all the models can be created without any
database errors. We can also do some more simple insertion and lookup tests
whilst we're here to show that the second of models do refer to the tables from
the first set.
# Insert some data into one set of models.
>>> a = A01.objects.create(f_a="foo", f_b=42)
>>> _ = B01.objects.create(fk_a=a, f_a="fred", f_b=1729)
>>> c = C01.objects.create(f_a="barney", f_b=1)
>>> c.mm_a = [a]
# ... and pull it out via the other set.
>>> A02.objects.all()
[<A02: foo>]
>>> b = B02.objects.all()[0]
>>> b
<B02: fred>
>>> b.fk_a
<A02: foo>
>>> C02.objects.filter(f_a=None)
[]
>>> C02.objects.filter(mm_a=a.id)
[<C02: barney>]
"""}