89 lines
3.1 KiB
C++
89 lines
3.1 KiB
C++
#include <cstdio>
|
|
#include <iostream>
|
|
#include <memory>
|
|
#include <stdexcept>
|
|
#include <string>
|
|
#include <sstream>
|
|
#include <array>
|
|
#include <algorithm>
|
|
#include <vector>
|
|
|
|
#ifdef _WIN32
|
|
#define popen _popen
|
|
#define pclose _pclose
|
|
#endif
|
|
|
|
std::string exec(const char* cmd) {
|
|
std::array<char, 128> buffer;
|
|
std::string result;
|
|
std::unique_ptr<FILE, decltype(&pclose)> pipe(popen(cmd, "r"), pclose);
|
|
if (!pipe) {
|
|
throw std::runtime_error("popen() failed!");
|
|
}
|
|
while (fgets(buffer.data(), buffer.size(), pipe.get()) != nullptr) {
|
|
result += buffer.data();
|
|
}
|
|
return result;
|
|
}
|
|
|
|
double readThroughput(std::string parseOutput) {
|
|
std::istringstream output(parseOutput);
|
|
std::string line;
|
|
double result = 0;
|
|
int numResults = 0;
|
|
while (std::getline(output, line)) {
|
|
int pos = 0;
|
|
for (int i=0; i<5; i++) {
|
|
pos = line.find('\t', pos);
|
|
if (pos < 0) {
|
|
std::cerr << "Command printed out a line with less than 5 fields in it:\n" << line << std::endl;
|
|
}
|
|
pos++;
|
|
}
|
|
result += std::stod(line.substr(pos));
|
|
numResults++;
|
|
}
|
|
return result / numResults;
|
|
}
|
|
|
|
const double INTERLEAVED_ATTEMPTS = 7;
|
|
|
|
int main(int argc, char *argv[]) {
|
|
if (argc != 3) {
|
|
std::cerr << "Usage: " << argv[0] << " <new parse cmd> <reference parse cmd>" << std::endl;
|
|
return 1;
|
|
}
|
|
std::vector<double> ref;
|
|
std::vector<double> newcode;
|
|
for (int attempt=0; attempt < INTERLEAVED_ATTEMPTS; attempt++) {
|
|
std::cout << "Attempt #" << (attempt+1) << " of " << INTERLEAVED_ATTEMPTS << std::endl;
|
|
|
|
// Read new throughput
|
|
double newThroughput = readThroughput(exec(argv[1]));
|
|
std::cout << "New throughput: " << newThroughput << std::endl;
|
|
newcode.push_back(newThroughput);
|
|
|
|
// Read reference throughput
|
|
double referenceThroughput = readThroughput(exec(argv[2]));
|
|
std::cout << "Ref throughput: " << referenceThroughput << std::endl;
|
|
ref.push_back(referenceThroughput);
|
|
}
|
|
// we check if the maximum of newcode is lower than minimum of ref, if so we have a problem so fail!
|
|
double worseref = *std::min_element(ref.begin(), ref.end());
|
|
double bestnewcode = *std::max_element(newcode.begin(), newcode.end());
|
|
double bestref = *std::max_element(ref.begin(), ref.end());
|
|
double worsenewcode = *std::min_element(newcode.begin(), newcode.end());
|
|
std::cout << "The new code has a throughput in " << worsenewcode << " -- " << bestnewcode << std::endl;
|
|
std::cout << "The reference code has a throughput in " << worseref << " -- " << bestref << std::endl;
|
|
if(bestnewcode < worseref) {
|
|
std::cerr << "You probably have a performance degradation." << std::endl;
|
|
return EXIT_FAILURE;
|
|
}
|
|
if(bestnewcode < worseref) {
|
|
std::cout << "You probably have a performance gain." << std::endl;
|
|
return EXIT_SUCCESS;
|
|
}
|
|
std::cout << "There is no obvious performance difference. A manual check might be needed." << std::endl;
|
|
return EXIT_SUCCESS;
|
|
}
|