orga0063
/
BootstrapAdmin11
4
0
Fork 0
Code Issues Pull Requests Projects Releases Wiki Activity

fix: popover button 在 safari 浏览器内工作不正常

This commit is contained in:
Argo Zhang 2019-08-14 14:09:26 +08:00
parent 48dc40ee33
commit 7f26cf4efe
No known key found for this signature in database
GPG Key ID: 152E398953DDF19F
1 changed files with 1 additions and 1 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

2
Bootstrap.Admin/wwwroot/js/healths.js
View File

@ -22,7 +22,7 @@
{ title: "检查结果", field: "Status", formatter: StatusFormatter },
{
title: "明细数据", field: "Data", formatter: function (value, row, index) {
return '<button class="detail btn btn-info" data-trigger="focus" data-container="body" data-toggle="popover" data-placement="left"><i class="fa fa-info"></i><span>明细</span></button>';
return '<a tabindex="0" role="button" class="detail btn btn-info" data-trigger="focus" data-container="body" data-toggle="popover" data-placement="left"><i class="fa fa-info"></i><span>明细</span></a>';
},
events: {
'click .detail': function (e, value, row, index) {