Fixed #25136 -- Documented Count('X', distinct=True) in aggregate topic guide.
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@ -184,17 +184,39 @@ of the ``annotate()`` clause is a ``QuerySet``; this ``QuerySet`` can be
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modified using any other ``QuerySet`` operation, including ``filter()``,
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``order_by()``, or even additional calls to ``annotate()``.
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Combining multiple aggregations
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-------------------------------
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Combining multiple aggregations with ``annotate()`` will `yield the wrong
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results <https://code.djangoproject.com/ticket/10060>`_, as multiple tables are
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cross joined. Due to the use of ``LEFT OUTER JOIN``, duplicate records will be
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generated if some of the joined tables contain more records than the others:
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>>> Book.objects.first().authors.count()
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2
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>>> Book.objects.first().chapters.count()
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3
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>>> q = Book.objects.annotate(Count('authors'), Count('chapters'))
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>>> q[0].authors__count
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6
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>>> q[0].chapters__count
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6
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For most aggregates, there is no way to avoid this problem, however, the
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:class:`~django.db.models.Count` aggregate has a ``distinct`` parameter that
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may help:
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>>> q = Book.objects.annotate(Count('authors', distinct=True), Count('chapters', distinct=True))
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>>> q[0].authors__count
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2
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>>> q[0].chapters__count
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3
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.. admonition:: If in doubt, inspect the SQL query!
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In order to understand what happens in your query, consider inspecting the
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``query`` property of your ``QuerySet``.
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For instance, combining multiple aggregations with ``annotate()`` will
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yield the wrong results, as `multiple tables are cross joined`_,
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resulting in duplicate row aggregations.
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.. _multiple tables are cross joined: https://code.djangoproject.com/ticket/10060
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Joins and aggregates
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====================
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