Fixed #5640 -- Added some extra error reporting when smart_unicode() or
force_unicode() raise a UnicodeDecodeError. This should at least help people identify which is the bad piece of data they passed in. About the best we can do here. git-svn-id: http://code.djangoproject.com/svn/django/trunk@6649 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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@ -1,8 +1,19 @@
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import types
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import urllib
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import datetime
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from django.utils.functional import Promise
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class DjangoUnicodeDecodeError(UnicodeDecodeError):
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def __init__(self, obj, *args):
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self.obj = obj
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UnicodeDecodeError.__init__(self, *args)
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def __str__(self):
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original = UnicodeDecodeError.__str__(self)
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return '%s. You passed in %r (%s)' % (original, self.obj,
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type(self.obj))
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class StrAndUnicode(object):
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"""
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A class whose __str__ returns its __unicode__ as a UTF-8 bytestring.
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@ -33,6 +44,7 @@ def force_unicode(s, encoding='utf-8', strings_only=False, errors='strict'):
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"""
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if strings_only and isinstance(s, (types.NoneType, int, long, datetime.datetime, datetime.date, datetime.time, float)):
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return s
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try:
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if not isinstance(s, basestring,):
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if hasattr(s, '__unicode__'):
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s = unicode(s)
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@ -40,6 +52,8 @@ def force_unicode(s, encoding='utf-8', strings_only=False, errors='strict'):
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s = unicode(str(s), encoding, errors)
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elif not isinstance(s, unicode):
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s = unicode(s, encoding, errors)
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except UnicodeDecodeError, e:
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raise DjangoUnicodeDecodeError(s, *e.args)
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return s
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def smart_str(s, encoding='utf-8', strings_only=False, errors='strict'):
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