Avoided related_name conflicts in tests
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@ -24,7 +24,7 @@ class Publisher(models.Model):
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return self.name
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class TaggedItem(models.Model):
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class ItemTag(models.Model):
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tag = models.CharField(max_length=100)
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content_type = models.ForeignKey(ContentType)
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object_id = models.PositiveIntegerField()
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@ -42,7 +42,7 @@ class Book(models.Model):
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contact = models.ForeignKey(Author, related_name='book_contact_set')
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publisher = models.ForeignKey(Publisher)
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pubdate = models.DateField()
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tags = generic.GenericRelation(TaggedItem)
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tags = generic.GenericRelation(ItemTag)
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class Meta:
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ordering = ('name',)
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@ -12,7 +12,7 @@ from django.test import TestCase, Approximate, skipUnlessDBFeature
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from django.utils import six
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from .models import (Author, Book, Publisher, Clues, Entries, HardbackBook,
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TaggedItem, WithManualPK)
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ItemTag, WithManualPK)
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class AggregationTests(TestCase):
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@ -993,18 +993,18 @@ class AggregationTests(TestCase):
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tests aggregations with generic reverse relations
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"""
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b = Book.objects.get(name='Practical Django Projects')
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TaggedItem.objects.create(object_id=b.id, tag='intermediate',
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ItemTag.objects.create(object_id=b.id, tag='intermediate',
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content_type=ContentType.objects.get_for_model(b))
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TaggedItem.objects.create(object_id=b.id, tag='django',
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ItemTag.objects.create(object_id=b.id, tag='django',
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content_type=ContentType.objects.get_for_model(b))
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# Assign a tag to model with same PK as the book above. If the JOIN
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# used in aggregation doesn't have content type as part of the
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# condition the annotation will also count the 'hi mom' tag for b.
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wmpk = WithManualPK.objects.create(id=b.pk)
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TaggedItem.objects.create(object_id=wmpk.id, tag='hi mom',
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ItemTag.objects.create(object_id=wmpk.id, tag='hi mom',
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content_type=ContentType.objects.get_for_model(wmpk))
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b = Book.objects.get(name__startswith='Paradigms of Artificial Intelligence')
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TaggedItem.objects.create(object_id=b.id, tag='intermediate',
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ItemTag.objects.create(object_id=b.id, tag='intermediate',
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content_type=ContentType.objects.get_for_model(b))
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self.assertEqual(Book.objects.aggregate(Count('tags')), {'tags__count': 3})
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