Fixed #20999 - Allow overriding formfield class with choices, without subclass restrictions.

Refs #18162. Thanks claudep and mjtamlyn for review.
This commit is contained in:
Carl Meyer 2013-08-29 21:44:37 -06:00
parent b04f8ddbaa
commit 7211741fc5
3 changed files with 22 additions and 16 deletions

View File

@ -636,7 +636,7 @@ class Field(object):
def save_form_data(self, instance, data):
setattr(instance, self.name, data)
def formfield(self, form_class=None, **kwargs):
def formfield(self, form_class=None, choices_form_class=None, **kwargs):
"""
Returns a django.forms.Field instance for this database Field.
"""
@ -657,7 +657,9 @@ class Field(object):
defaults['coerce'] = self.to_python
if self.null:
defaults['empty_value'] = None
if form_class is None or not issubclass(form_class, forms.TypedChoiceField):
if choices_form_class is not None:
form_class = choices_form_class
else:
form_class = forms.TypedChoiceField
# Many of the subclass-specific formfield arguments (min_value,
# max_value) don't apply for choice fields, so be sure to only pass

View File

@ -617,17 +617,23 @@ prepared with :meth:`.get_prep_lookup`.
Specifying the form field for a model field
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
.. method:: Field.formfield(self, form_class=forms.CharField, **kwargs)
.. method:: Field.formfield(self, form_class=None, choices_form_class=None, **kwargs)
Returns the default form field to use when this field is displayed in a model.
This method is called by the :class:`~django.forms.ModelForm` helper.
Returns the default form field to use when this model field is displayed in a
form. This method is called by the :class:`~django.forms.ModelForm` helper.
The form field class can be specified via the ``form_class`` and
``choices_form_class`` arguments; the latter is used if the field has choices
specified, the former otherwise. If these arguments are not provided,
:class:`~django.forms.CharField` or :class:`~django.forms.TypedChoiceField`
will be used.
All of the ``kwargs`` dictionary is passed directly to the form field's
``__init__()`` method. Normally, all you need to do is set up a good default
for the ``form_class`` argument and then delegate further handling to the
parent class. This might require you to write a custom form field (and even a
form widget). See the :doc:`forms documentation </topics/forms/index>` for
information about this.
for the ``form_class`` (and maybe ``choices_form_class``) argument and then
delegate further handling to the parent class. This might require you to write
a custom form field (and even a form widget). See the :doc:`forms documentation
</topics/forms/index>` for information about this.
Continuing our ongoing example, we can write the :meth:`.formfield` method as::

View File

@ -78,14 +78,12 @@ class BasicFieldTests(test.TestCase):
self.assertEqual(m._meta.get_field('id').verbose_name, 'verbose pk')
def test_formclass_with_choices(self):
# regression for 18162
class CustomChoiceField(forms.TypedChoiceField):
pass
choices = [('a@b.cc', 'a@b.cc'), ('b@b.cc', 'b@b.cc')]
def test_choices_form_class(self):
"""Can supply a custom choices form class. Regression for #20999."""
choices = [('a', 'a')]
field = models.CharField(choices=choices)
klass = CustomChoiceField
self.assertIsInstance(field.formfield(form_class=klass), klass)
klass = forms.TypedMultipleChoiceField
self.assertIsInstance(field.formfield(choices_form_class=klass), klass)
class DecimalFieldTests(test.TestCase):