Fixed #1796 -- only load a single copy of each model, even when it is
referenced via different import paths. Solves a problem with many-to-many relations being set up incorrectly. Thanks to Curtis Thompson, Luke Plant and Simon Willison for some excellent debugging of the problem. Refs #2232 (may also have fixed that). git-svn-id: http://code.djangoproject.com/svn/django/trunk@3202 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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@ -2,6 +2,8 @@
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from django.conf import settings
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from django.core.exceptions import ImproperlyConfigured
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import sys
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import os
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__all__ = ('get_apps', 'get_app', 'get_models', 'get_model', 'register_models')
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@ -91,4 +93,14 @@ def register_models(app_label, *models):
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# in the _app_models dictionary
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model_name = model._meta.object_name.lower()
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model_dict = _app_models.setdefault(app_label, {})
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if model_dict.has_key(model_name):
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# The same model may be imported via different paths (e.g.
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# appname.models and project.appname.models). We use the source
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# filename as a means to detect identity.
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fname1 = os.path.normpath(sys.modules[model.__module__].__file__)
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fname2 = os.path.normpath(sys.modules[model_dict[model_name].__module__].__file__)
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# Since the filename extension could be .py the first time and .pyc
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# or .pyo the second time, ignore the extension when comparing.
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if os.path.splitext(fname1)[0] == os.path.splitext(fname2)[0]:
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continue
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model_dict[model_name] = model
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