Fixed #8023 -- Allow filtering of DecimalFields (in models) using strings.

At the same time, checked all other cases of db_prep_value() to ensure they
aren't making the same mistake.


git-svn-id: http://code.djangoproject.com/svn/django/trunk@8143 bcc190cf-cafb-0310-a4f2-bffc1f526a37
This commit is contained in:
Malcolm Tredinnick 2008-07-30 00:18:49 +00:00
parent 1ba2d6888f
commit 281f2b74bf
2 changed files with 16 additions and 5 deletions

View File

@ -732,8 +732,8 @@ class DecimalField(Field):
return util.format_number(value, self.max_digits, self.decimal_places)
def get_db_prep_value(self, value):
return connection.ops.value_to_db_decimal(value, self.max_digits,
self.decimal_places)
return connection.ops.value_to_db_decimal(self.to_python(value),
self.max_digits, self.decimal_places)
def get_manipulator_field_objs(self):
return [curry(oldforms.DecimalField, max_digits=self.max_digits, decimal_places=self.decimal_places)]

View File

@ -1,8 +1,14 @@
from django.db import models
try:
import decimal
except ImportError:
from django.utils import _decimal as decimal # Python 2.3 fallback
class Foo(models.Model):
a = models.CharField(max_length=10)
d = models.DecimalField(max_digits=5, decimal_places=3)
def get_foo():
return Foo.objects.get(id=1)
@ -29,7 +35,7 @@ class Whiz(models.Model):
__test__ = {'API_TESTS':"""
# Create a couple of Places.
>>> f = Foo.objects.create(a='abc')
>>> f = Foo.objects.create(a='abc', d=decimal.Decimal("12.34"))
>>> f.id
1
>>> b = Bar(b = "bcd")
@ -67,5 +73,10 @@ None
>>> w.get_c_display()
u''
# Regression test for #8023: should be able to filter decimal fields using
# strings (which is what gets passed through from, e.g., the admin interface).
>>> Foo.objects.filter(d=u'1.23')
[]
"""}