Removed lexer_factory() and parser_factory() functions in django.template, simplifying the compile_string() logic

git-svn-id: http://code.djangoproject.com/svn/django/trunk@6973 bcc190cf-cafb-0310-a4f2-bffc1f526a37
This commit is contained in:
Adrian Holovaty 2007-12-22 19:28:21 +00:00
parent eb95a50cd6
commit 36a06edcdf
1 changed files with 7 additions and 16 deletions

View File

@ -175,8 +175,13 @@ class Template(object):
def compile_string(template_string, origin):
"Compiles template_string into NodeList ready for rendering"
lexer = lexer_factory(template_string, origin)
parser = parser_factory(lexer.tokenize())
if settings.TEMPLATE_DEBUG:
from debug import DebugLexer, DebugParser
lexer_class, parser_class = DebugLexer, DebugParser
else:
lexer_class, parser_class = Lexer, Parser
lexer = lexer_class(template_string, origin)
parser = parser_class(lexer.tokenize())
return parser.parse()
class Token(object):
@ -334,20 +339,6 @@ class Parser(object):
else:
raise TemplateSyntaxError("Invalid filter: '%s'" % filter_name)
def lexer_factory(*args, **kwargs):
if settings.TEMPLATE_DEBUG:
from debug import DebugLexer
return DebugLexer(*args, **kwargs)
else:
return Lexer(*args, **kwargs)
def parser_factory(*args, **kwargs):
if settings.TEMPLATE_DEBUG:
from debug import DebugParser
return DebugParser(*args, **kwargs)
else:
return Parser(*args, **kwargs)
class TokenParser(object):
"""
Subclass this and implement the top() method to parse a template line. When