diff --git a/django/utils/crypto.py b/django/utils/crypto.py
index 74dd9fd7b08..e5ae2108f29 100644
--- a/django/utils/crypto.py
+++ b/django/utils/crypto.py
@@ -1,11 +1,9 @@
 """
 Django's standard crypto functions and utilities.
 """
-import binascii
 import hashlib
 import hmac
 import random
-import struct
 import time
 
 from django.conf import settings
@@ -73,115 +71,17 @@ def get_random_string(length=12,
     return ''.join(random.choice(allowed_chars) for i in range(length))
 
 
-if hasattr(hmac, "compare_digest"):
-    # Prefer the stdlib implementation, when available.
-    def constant_time_compare(val1, val2):
-        return hmac.compare_digest(force_bytes(val1), force_bytes(val2))
-else:
-    def constant_time_compare(val1, val2):
-        """
-        Returns True if the two strings are equal, False otherwise.
-
-        The time taken is independent of the number of characters that match.
-
-        For the sake of simplicity, this function executes in constant time only
-        when the two strings have the same length. It short-circuits when they
-        have different lengths. Since Django only uses it to compare hashes of
-        known expected length, this is acceptable.
-        """
-        if len(val1) != len(val2):
-            return False
-        result = 0
-        if isinstance(val1, bytes) and isinstance(val2, bytes):
-            for x, y in zip(val1, val2):
-                result |= x ^ y
-        else:
-            for x, y in zip(val1, val2):
-                result |= ord(x) ^ ord(y)
-        return result == 0
+def constant_time_compare(val1, val2):
+    """Return True if the two strings are equal, False otherwise."""
+    return hmac.compare_digest(force_bytes(val1), force_bytes(val2))
 
 
-def _bin_to_long(x):
-    """
-    Convert a binary string into a long integer
-
-    This is a clever optimization for fast xor vector math
-    """
-    return int(binascii.hexlify(x), 16)
-
-
-def _long_to_bin(x, hex_format_string):
-    """
-    Convert a long integer into a binary string.
-    hex_format_string is like "%020x" for padding 10 characters.
-    """
-    return binascii.unhexlify((hex_format_string % x).encode('ascii'))
-
-
-if hasattr(hashlib, "pbkdf2_hmac"):
-    def pbkdf2(password, salt, iterations, dklen=0, digest=None):
-        """
-        Implements PBKDF2 with the same API as Django's existing
-        implementation, using the stdlib.
-
-        This is used in Python 2.7.8+ and 3.4+.
-        """
-        if digest is None:
-            digest = hashlib.sha256
-        if not dklen:
-            dklen = None
-        password = force_bytes(password)
-        salt = force_bytes(salt)
-        return hashlib.pbkdf2_hmac(
-            digest().name, password, salt, iterations, dklen)
-else:
-    def pbkdf2(password, salt, iterations, dklen=0, digest=None):
-        """
-        Implements PBKDF2 as defined in RFC 2898, section 5.2
-
-        HMAC+SHA256 is used as the default pseudo random function.
-
-        As of 2014, 100,000 iterations was the recommended default which took
-        100ms on a 2.7Ghz Intel i7 with an optimized implementation. This is
-        probably the bare minimum for security given 1000 iterations was
-        recommended in 2001. This code is very well optimized for CPython and
-        is about five times slower than OpenSSL's implementation. Look in
-        django.contrib.auth.hashers for the present default, it is lower than
-        the recommended 100,000 because of the performance difference between
-        this and an optimized implementation.
-        """
-        assert iterations > 0
-        if not digest:
-            digest = hashlib.sha256
-        password = force_bytes(password)
-        salt = force_bytes(salt)
-        hlen = digest().digest_size
-        if not dklen:
-            dklen = hlen
-        if dklen > (2 ** 32 - 1) * hlen:
-            raise OverflowError('dklen too big')
-        L = -(-dklen // hlen)
-        r = dklen - (L - 1) * hlen
-
-        hex_format_string = "%%0%ix" % (hlen * 2)
-
-        inner, outer = digest(), digest()
-        if len(password) > inner.block_size:
-            password = digest(password).digest()
-        password += b'\x00' * (inner.block_size - len(password))
-        inner.update(password.translate(hmac.trans_36))
-        outer.update(password.translate(hmac.trans_5C))
-
-        def F(i):
-            u = salt + struct.pack(b'>I', i)
-            result = 0
-            for j in range(int(iterations)):
-                dig1, dig2 = inner.copy(), outer.copy()
-                dig1.update(u)
-                dig2.update(dig1.digest())
-                u = dig2.digest()
-                result ^= _bin_to_long(u)
-            return _long_to_bin(result, hex_format_string)
-
-        T = [F(x) for x in range(1, L)]
-        return b''.join(T) + F(L)[:r]
+def pbkdf2(password, salt, iterations, dklen=0, digest=None):
+    """Return the hash of password using pbkdf2."""
+    if digest is None:
+        digest = hashlib.sha256
+    if not dklen:
+        dklen = None
+    password = force_bytes(password)
+    salt = force_bytes(salt)
+    return hashlib.pbkdf2_hmac(digest().name, password, salt, iterations, dklen)