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Fixed #24190 -- Clarified len(queryset)
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@ -57,11 +57,10 @@ You can evaluate a ``QuerySet`` in the following ways:
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* **len().** A ``QuerySet`` is evaluated when you call ``len()`` on it.
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This, as you might expect, returns the length of the result list.
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Note: *Don't* use ``len()`` on ``QuerySet``\s if all you want to do is
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determine the number of records in the set. It's much more efficient to
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handle a count at the database level, using SQL's ``SELECT COUNT(*)``,
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and Django provides a ``count()`` method for precisely this reason. See
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``count()`` below.
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Note: If you only need to determine the number of records in the set (and
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don't need the actual objects), it's much more efficient to handle a count
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at the database level using SQL's ``SELECT COUNT(*)``. Django provides a
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:meth:`~QuerySet.count` method for precisely this reason.
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* **list().** Force evaluation of a ``QuerySet`` by calling ``list()`` on
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it. For example::
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@ -76,9 +75,8 @@ You can evaluate a ``QuerySet`` in the following ways:
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if Entry.objects.filter(headline="Test"):
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print("There is at least one Entry with the headline Test")
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Note: *Don't* use this if all you want to do is determine if at least one
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result exists, and don't need the actual objects. It's more efficient to
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use :meth:`~QuerySet.exists` (see below).
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Note: If you only want to determine if at least one result exists (and don't
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need the actual objects), it's more efficient to use :meth:`~QuerySet.exists`.
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.. _pickling QuerySets:
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@ -1805,6 +1803,11 @@ Depending on which database you're using (e.g. PostgreSQL vs. MySQL),
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is an underlying implementation quirk that shouldn't pose any real-world
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problems.
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Note that if you want the number of items in a ``QuerySet`` and are also
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retrieving model instances from it (for example, by iterating over it), it's
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probably more efficient to use ``len(queryset)`` which won't cause an extra
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database query like ``count()`` would.
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in_bulk
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~~~~~~~
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