forked from p15670423/monkey
Make deploy_linux.sh download the configuration, avoiding need for duplicate git clone.
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@ -15,7 +15,9 @@ Don't forget to add python to PATH or do so while installing it via this script.
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Linux deployment script is meant for Ubuntu 16.x machines.
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You must have root permissions, but don't run the script as root.<br>
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Launch deploy_linux.sh from scripts directory.<br>
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`wget https://raw.githubusercontent.com/guardicore/monkey/develop/deployment_scripts/deploy_linux.sh`
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Then execute the resulting script with your shell.
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First argument should be an absolute path of an empty directory (script will create one if doesn't exist, default is ./infection_monkey).
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Second parameter is the branch you want to clone (develop by default).
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Example usages:<br>
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@ -1,10 +1,31 @@
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#!/bin/bash
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source config
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exists() {
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command -v "$1" >/dev/null 2>&1
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}
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is_root() {
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return $(id -u)
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}
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has_sudo() {
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# 0 true, 1 false
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timeout 1 sudo id && return 0 || return 1
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}
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config_branch=${2:-"develop"}
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config_url="https://raw.githubusercontent.com/guardicore/monkey/"$config_branch"/deployment_scripts/config"
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if exists curl; then
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file=$(mktemp)
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curl -s -o $file "$config_url"
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source $file
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rm $file
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else
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echo 'Your system does not have curl, exiting'
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exit 1
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fi
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# Setup monkey either in dir required or current dir
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monkey_home=${1:-$(pwd)}
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if [[ $monkey_home == $(pwd) ]]; then
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@ -30,8 +51,13 @@ log_message() {
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echo -e "-------------------------------------------\n"
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}
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sudo -v
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if [[ $? != 0 ]]; then
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if is_root; then
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echo "Please don't runt this script as root"
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exit 1
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fi
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HAS_SUDO=$(has_sudo)
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if [[ ! $HAS_SUDO ]]; then
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echo "You need root permissions for some of this script operations. Quiting."
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exit 1
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fi
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