fix(功能用例): 修复可以重复关联需求问题
--bug=1044284 --user=郭雨琦 https://www.tapd.cn/55049933/bugtrace/bugs/view/1155049933001044284
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@ -273,12 +273,8 @@ public class FunctionalCaseDemandService {
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//校验重复
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List<FunctionalCaseDemand> functionalCaseDemands = existMap.get(demandDTO.getDemandId());
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if (CollectionUtils.isNotEmpty(functionalCaseDemands)) {
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List<FunctionalCaseDemand> list = functionalCaseDemands.stream().filter(t -> StringUtils.equalsIgnoreCase(t.getDemandId(), functionalCaseDemand.getDemandId()) && StringUtils.equalsIgnoreCase(t.getParent(), functionalCaseDemand.getParent())
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&& StringUtils.equalsIgnoreCase(t.getDemandName(), functionalCaseDemand.getDemandName()) && StringUtils.equalsIgnoreCase(t.getDemandUrl(), functionalCaseDemand.getDemandUrl())).toList();
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if (CollectionUtils.isNotEmpty(list)) {
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continue;
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}
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}
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//校验当前关联的需求在系统或传入的数据结构中是否带有父节点,如果有置为true,用来做查询的root节点
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List<FunctionalCaseDemand> functionalCaseDemandParents = existMap.get(demandDTO.getParent());
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List<DemandDTO> demandDTOList1 = insertMap.get(demandDTO.getParent());
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