Fixed typos and improved documentation for permission_required decorator addition from [3779]
git-svn-id: http://code.djangoproject.com/svn/django/trunk@3835 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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@ -29,8 +29,8 @@ login_required.__doc__ = (
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def permission_required(perm, login_url=LOGIN_URL):
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"""
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Decorator for views that checks if a user has a particular permission
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enabled, redirectiing to the log-in page if necessary.
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Decorator for views that checks whether a user has a particular permission
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enabled, redirecting to the log-in page if necessary.
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"""
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return user_passes_test(lambda u: u.has_perm(perm), login_url=login_url)
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@ -456,9 +456,9 @@ As a shortcut, you can use the convenient ``user_passes_test`` decorator::
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# ...
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my_view = user_passes_test(lambda u: u.has_perm('polls.can_vote'))(my_view)
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We are using this particular test as a relatively simple example, however be
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aware that if you just want to test if a permission is available to a user,
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you can use the ``permission_required()`` decorator described below.
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We're using this particular test as a relatively simple example. However, if
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you just want to test whether a permission is available to a user, you can use
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the ``permission_required()`` decorator, described later in this document.
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Here's the same thing, using Python 2.4's decorator syntax::
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@ -495,20 +495,30 @@ Example in Python 2.4 syntax::
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The permission_required decorator
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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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Since checking whether a user has a particular permission available to them is a
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relatively common operation, Django provides a shortcut for that particular
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case: the ``permission_required()`` decorator. Using this decorator, the
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earlier example can be written as::
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**New in Django development version**
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It's a relatively common task to check whether a user has a particular
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permission. For that reason, Django provides a shortcut for that case: the
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``permission_required()`` decorator. Using this decorator, the earlier example
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can be written as::
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from django.contrib.auth.decorators import permission_required
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def my_view(request):
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# ...
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my_view = permission_required('polls.can_vote')(my_view)
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Note that ``permission_required()`` also takes an optional ``login_url``
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parameter.
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parameter. Example::
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from django.contrib.auth.decorators import permission_required
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def my_view(request):
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# ...
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my_view = permission_required('polls.can_vote', login_url='/loginpage/')(my_view)
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As in the ``login_required`` decorator, ``login_url`` defaults to
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``'/accounts/login/'``.
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Limiting access to generic views
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--------------------------------
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