Fixed #16293: Document a way to return dicts with column names from a DB cursor.
git-svn-id: http://code.djangoproject.com/svn/django/trunk@16808 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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@ -240,6 +240,30 @@ alias::
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# Your code here...
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# Your code here...
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transaction.commit_unless_managed(using='my_db_alias')
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transaction.commit_unless_managed(using='my_db_alias')
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By default, the Python DB API will return results without their field
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names, which means you end up with a ``list`` of values, rather than a
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``dict``. At a small performance cost, you can return results as a
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``dict`` by using something like this::
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def dictfetchall(cursor):
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"Returns all rows from a cursor as a dict"
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desc = cursor.description
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return [
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dict(zip([col[0] for col in desc], row))
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for row in cursor.fetchall()
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]
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Here is an example of the difference between the two::
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>>> cursor.execute("SELECT id, parent_id from test LIMIT 2");
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>>> cursor.fetchall()
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((54360982L, None), (54360880L, None))
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>>> cursor.execute("SELECT id, parent_id from test LIMIT 2");
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>>> dictfetchall(cursor)
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[{'parent_id': None, 'id': 54360982L}, {'parent_id': None, 'id': 54360880L}]
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.. _transactions-and-raw-sql:
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.. _transactions-and-raw-sql:
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Transactions and raw SQL
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Transactions and raw SQL
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