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Fixed #3846 -- Fixed misleading variable name in 'startapp' code. Thanks, MarioGonzalez 

git-svn-id: http://code.djangoproject.com/svn/django/trunk@4989 bcc190cf-cafb-0310-a4f2-bffc1f526a37
This commit is contained in:
Adrian Holovaty 2007-04-09 20:57:07 +00:00
parent a02e13c7da
commit 4326de3fc1
1 changed files with 4 additions and 3 deletions
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7
django/core/management.py
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@ -789,11 +789,12 @@ def startapp(app_name, directory):
# Determine the project_name a bit naively -- by looking at the name of
# the parent directory.
project_dir = os.path.normpath(os.path.join(directory, '..'))
project_name = os.path.basename(project_dir)
if app_name == os.path.basename(directory):
parent_dir = os.path.basename(project_dir)
project_name = os.path.basename(directory)
if app_name == project_name:
sys.stderr.write(style.ERROR("Error: You cannot create an app with the same name (%r) as your project.\n" % app_name))
sys.exit(1)
_start_helper('app', app_name, directory, project_name)
_start_helper('app', app_name, directory, parent_dir)
startapp.help_doc = "Creates a Django app directory structure for the given app name in the current directory."
startapp.args = "[appname]"