Fixed #5824 -- For the `startapp` command, pass the true project name to the `copy_helper` function instead of the name of the project's parent directory.

git-svn-id: http://code.djangoproject.com/svn/django/trunk@6621 bcc190cf-cafb-0310-a4f2-bffc1f526a37
This commit is contained in:
Gary Wilson Jr 2007-10-27 16:05:59 +00:00
parent 2dfad61fcc
commit 62c574e765
1 changed files with 4 additions and 5 deletions

View File

@ -14,14 +14,13 @@ class Command(LabelCommand):
def handle_label(self, app_name, directory=None, **options): def handle_label(self, app_name, directory=None, **options):
if directory is None: if directory is None:
directory = os.getcwd() directory = os.getcwd()
# Determine the project_name a bit naively -- by looking at the name of # Determine the project_name by using the basename of directory,
# the parent directory. # which should be the full path of the project directory (or the
project_dir = os.path.normpath(os.path.join(directory, os.pardir)) # current directory if no directory was passed).
parent_dir = os.path.basename(project_dir)
project_name = os.path.basename(directory) project_name = os.path.basename(directory)
if app_name == project_name: if app_name == project_name:
raise CommandError("You cannot create an app with the same name (%r) as your project." % app_name) raise CommandError("You cannot create an app with the same name (%r) as your project." % app_name)
copy_helper(self.style, 'app', app_name, directory, parent_dir) copy_helper(self.style, 'app', app_name, directory, project_name)
class ProjectCommand(Command): class ProjectCommand(Command):
help = "Creates a Django app directory structure for the given app name in this project's directory." help = "Creates a Django app directory structure for the given app name in this project's directory."