Refs #18586 -- Split up order_with_respect_to tests

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Helen ST 2014-11-27 22:00:28 +00:00 committed by Tim Graham
parent 765fa36d57
commit 7daf00679d
1 changed files with 40 additions and 28 deletions

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@ -10,61 +10,73 @@ from .models import Post, Question, Answer
class OrderWithRespectToTests(TestCase):
def test_basic(self):
q1 = Question.objects.create(text="Which Beatle starts with the letter 'R'?")
q2 = Question.objects.create(text="What is your name?")
Answer.objects.create(text="John", question=q1)
Answer.objects.create(text="Jonno", question=q2)
Answer.objects.create(text="Paul", question=q1)
Answer.objects.create(text="Paulo", question=q2)
Answer.objects.create(text="George", question=q1)
Answer.objects.create(text="Ringo", question=q1)
@classmethod
def setUpTestData(cls):
cls.q1 = Question.objects.create(text="Which Beatle starts with the letter 'R'?")
Answer.objects.create(text="John", question=cls.q1)
Answer.objects.create(text="Paul", question=cls.q1)
Answer.objects.create(text="George", question=cls.q1)
Answer.objects.create(text="Ringo", question=cls.q1)
# The answers will always be ordered in the order they were inserted.
def test_default_to_insertion_order(self):
# Answers will always be ordered in the order they were inserted.
self.assertQuerysetEqual(
q1.answer_set.all(), [
self.q1.answer_set.all(), [
"John", "Paul", "George", "Ringo",
],
attrgetter("text"),
)
def test_previous_and_next_in_order(self):
# We can retrieve the answers related to a particular object, in the
# order they were created, once we have a particular object.
a1 = Answer.objects.filter(question=q1)[0]
a1 = Answer.objects.filter(question=self.q1)[0]
self.assertEqual(a1.text, "John")
a2 = a1.get_next_in_order()
self.assertEqual(a2.text, "Paul")
a4 = list(Answer.objects.filter(question=q1))[-1]
self.assertEqual(a4.text, "Ringo")
self.assertEqual(a4.get_previous_in_order().text, "George")
self.assertEqual(a1.get_next_in_order().text, "Paul")
# Determining (and setting) the ordering for a particular item is also
# possible.
id_list = [o.pk for o in q1.answer_set.all()]
self.assertEqual(a2.question.get_answer_order(), id_list)
a2 = list(Answer.objects.filter(question=self.q1))[-1]
self.assertEqual(a2.text, "Ringo")
self.assertEqual(a2.get_previous_in_order().text, "George")
a5 = Answer.objects.create(text="Number five", question=q1)
def test_item_ordering(self):
# We can retrieve the ordering of the queryset from a particular item.
a1 = Answer.objects.filter(question=self.q1)[1]
id_list = [o.pk for o in self.q1.answer_set.all()]
self.assertEqual(a1.question.get_answer_order(), id_list)
# It doesn't matter which answer we use to check the order, it will
# always be the same.
a2 = Answer.objects.create(text="Number five", question=self.q1)
self.assertEqual(
a2.question.get_answer_order(), a5.question.get_answer_order()
a1.question.get_answer_order(), a2.question.get_answer_order()
)
# The ordering can be altered:
id_list = [o.pk for o in q1.answer_set.all()]
def test_change_ordering(self):
# The ordering can be altered
a = Answer.objects.create(text="Number five", question=self.q1)
# Swap the last two items in the order list
id_list = [o.pk for o in self.q1.answer_set.all()]
x = id_list.pop()
id_list.insert(-1, x)
self.assertNotEqual(a5.question.get_answer_order(), id_list)
a5.question.set_answer_order(id_list)
# By default, the ordering is different from the swapped version
self.assertNotEqual(a.question.get_answer_order(), id_list)
# Change the ordering to the swapped version -
# this changes the ordering of the queryset.
a.question.set_answer_order(id_list)
self.assertQuerysetEqual(
q1.answer_set.all(), [
self.q1.answer_set.all(), [
"John", "Paul", "George", "Number five", "Ringo"
],
attrgetter("text")
)
class OrderWithRespectToTests2(TestCase):
def test_recursive_ordering(self):
p1 = Post.objects.create(title='1')
p2 = Post.objects.create(title='2')