Fixed #7366 -- Modified a few expected test outputs to remove the dependency on dictionary ordering. Thanks for the patch, Leo Soto.
git-svn-id: http://code.djangoproject.com/svn/django/trunk@7575 bcc190cf-cafb-0310-a4f2-bffc1f526a37
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@ -401,8 +401,9 @@ True
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# The 'select' argument to extra() supports names with dashes in them, as long
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# The 'select' argument to extra() supports names with dashes in them, as long
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# as you use values().
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# as you use values().
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>>> Article.objects.filter(pub_date__year=2008).extra(select={'dashed-value': '1'}).values('headline', 'dashed-value')
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>>> dicts = Article.objects.filter(pub_date__year=2008).extra(select={'dashed-value': '1'}).values('headline', 'dashed-value')
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[{'headline': u'Article 11', 'dashed-value': 1}, {'headline': u'Article 12', 'dashed-value': 1}]
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>>> [sorted(d.items()) for d in dicts]
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[[('dashed-value', 1), ('headline', u'Article 11')], [('dashed-value', 1), ('headline', u'Article 12')]]
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# If you use 'select' with extra() and names containing dashes on a query
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# If you use 'select' with extra() and names containing dashes on a query
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# that's *not* a values() query, those extra 'select' values will silently be
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# that's *not* a values() query, those extra 'select' values will silently be
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@ -110,8 +110,9 @@ __test__ = {'API_TESTS':"""
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>>> Article.objects.filter(Q(headline__startswith='Hello') | Q(headline__contains='bye')).count()
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>>> Article.objects.filter(Q(headline__startswith='Hello') | Q(headline__contains='bye')).count()
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3
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3
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>>> list(Article.objects.filter(Q(headline__startswith='Hello'), Q(headline__contains='bye')).values())
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>>> dicts = list(Article.objects.filter(Q(headline__startswith='Hello'), Q(headline__contains='bye')).values())
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[{'headline': u'Hello and goodbye', 'pub_date': datetime.datetime(2005, 11, 29, 0, 0), 'id': 3}]
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>>> [sorted(d.items()) for d in dicts]
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[[('headline', u'Hello and goodbye'), ('id', 3), ('pub_date', datetime.datetime(2005, 11, 29, 0, 0))]]
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>>> Article.objects.filter(Q(headline__startswith='Hello')).in_bulk([1,2])
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>>> Article.objects.filter(Q(headline__startswith='Hello')).in_bulk([1,2])
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{1: <Article: Hello>}
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{1: <Article: Hello>}
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@ -226,15 +226,17 @@ u'some <b>html</b> with alert("You smell") disallowed tags'
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>>> striptags(u'some <b>html</b> with <script>alert("You smell")</script> disallowed <img /> tags')
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>>> striptags(u'some <b>html</b> with <script>alert("You smell")</script> disallowed <img /> tags')
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u'some html with alert("You smell") disallowed tags'
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u'some html with alert("You smell") disallowed tags'
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>>> dictsort([{'age': 23, 'name': 'Barbara-Ann'},
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>>> sorted_dicts = dictsort([{'age': 23, 'name': 'Barbara-Ann'},
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... {'age': 63, 'name': 'Ra Ra Rasputin'},
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... {'age': 63, 'name': 'Ra Ra Rasputin'},
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... {'name': 'Jonny B Goode', 'age': 18}], 'age')
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... {'name': 'Jonny B Goode', 'age': 18}], 'age')
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[{'age': 18, 'name': 'Jonny B Goode'}, {'age': 23, 'name': 'Barbara-Ann'}, {'age': 63, 'name': 'Ra Ra Rasputin'}]
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>>> [sorted(dict.items()) for dict in sorted_dicts]
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[[('age', 18), ('name', 'Jonny B Goode')], [('age', 23), ('name', 'Barbara-Ann')], [('age', 63), ('name', 'Ra Ra Rasputin')]]
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>>> dictsortreversed([{'age': 23, 'name': 'Barbara-Ann'},
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>>> sorted_dicts = dictsortreversed([{'age': 23, 'name': 'Barbara-Ann'},
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... {'age': 63, 'name': 'Ra Ra Rasputin'},
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... {'age': 63, 'name': 'Ra Ra Rasputin'},
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... {'name': 'Jonny B Goode', 'age': 18}], 'age')
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... {'name': 'Jonny B Goode', 'age': 18}], 'age')
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[{'age': 63, 'name': 'Ra Ra Rasputin'}, {'age': 23, 'name': 'Barbara-Ann'}, {'age': 18, 'name': 'Jonny B Goode'}]
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>>> [sorted(dict.items()) for dict in sorted_dicts]
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[[('age', 63), ('name', 'Ra Ra Rasputin')], [('age', 23), ('name', 'Barbara-Ann')], [('age', 18), ('name', 'Jonny B Goode')]]
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>>> first([0,1,2])
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>>> first([0,1,2])
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0
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0
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@ -503,8 +503,9 @@ True
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# Despite having some extra aliases in the query, we can still omit them in a
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# Despite having some extra aliases in the query, we can still omit them in a
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# values() query.
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# values() query.
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>>> qs.values('id', 'rank').order_by('id')
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>>> dicts = qs.values('id', 'rank').order_by('id')
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[{'id': 1, 'rank': 2}, {'id': 2, 'rank': 1}, {'id': 3, 'rank': 3}]
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>>> [sorted(d.items()) for d in dicts]
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[[('id', 1), ('rank', 2)], [('id', 2), ('rank', 1)], [('id', 3), ('rank', 3)]]
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Bugs #2874, #3002
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Bugs #2874, #3002
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>>> qs = Item.objects.select_related().order_by('note__note', 'name')
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>>> qs = Item.objects.select_related().order_by('note__note', 'name')
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